standard enthalpy of vapourisation delta H for water at 100c is 40.66kj per mol.the internal energy of vapourisation of water at 100c? [in kj per mol] is
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If there is no air drag then maximum height,
H=u^2/2g=14×14/2×9.8=10m
But due to air drag ball reaches up to height 8m only.
So, loss in energy
=mg(10−8)
=0.5×9.8×2=9.8J
H=u^2/2g=14×14/2×9.8=10m
But due to air drag ball reaches up to height 8m only.
So, loss in energy
=mg(10−8)
=0.5×9.8×2=9.8J
nikhilsury13:
what is this?/
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∆H=∆E+P∆V
Vf>Vi. when water convert into vapour from liquid
so. ∆H>∆E
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