start?
A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motion is 10 ms 2
in the downward direction, what
will be the height attained by the
stone and how much time will it
take to reach there?
Answers
Answered by
12
Answer:
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Answered by
4
Answer:
1.25 m is the distance it covered
Explanation:
as we know,
2aS=v^2 - u^2
then,
2×-10×S=(0)^2 - (5)^2
-20S=-25
S= 1.25 m
abcd941:
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