Physics, asked by kajal6955, 5 months ago

Starting from a stationary position a bus attains a velocity of 6m/s in 30s .Then the driver of the bus applies a brake such that the velocity of the bus comes down to 4m/s in the next 5s .Cal culate the arceleration of the bus in both cases.​

Answers

Answered by MystícPhoeníx
78

• Acceleration in 1st Case 0.2m/s².

• Acceleration in 2nd Case 0.4m/s².

Explanation:

Solution:-

Firstly we calculate the acceleration in 1st condition.

  • Initial velocity ,u = 0m/s
  • Final velocity ,v = 6m/s
  • Time taken ,t = 30 s

we have to calculate the acceleration of the bus . As we know that acceleration is defined as the rate of change of velocity at per unit.

a = v-u/t

where,

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 6-0/30

→ a = 6/30

→ a = 1/5

→ a = 0.2 m/s²

  • Hence, the acceleration of bus in 1st case is 0.2m/.

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Now, we have to calculate the acceleration of bus in 2nd case.

  • Final velocity ,v = 4m/s
  • Initial velocity ,u = 6m/s
  • Time taken ,t = 5

Substitute the value we get

→ a = v-u/t

→ a = 4-6/5

→ a = -2/5

→ a = -0.4m/s²

Here Negative sign show retardation

  • Hence, the acceleration of the bus in 2nd case is 0.4m/.
Answered by itzgeniuspadhaku
23

Answer:

in first case,

initial velocity "u" = 0 m/s

final velocity "v"= 6m/s

time = 30 s

acceleration = final velocity- initial velocity/time

= 6-0/30

= 6/30

= 0.2 m/s²

in second case,

initial velocity "u" = 6m/s

final velocity "v" = 4m/s

time = 5 s

acceleration = final velocity - initial velocity/ time

= 4-6/5

= -2/5

= - 0.4m/s²

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