Question

Starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6m/s in

30s. Then he applies brakes such that the velocity of bicycle comes down to 4m/s in the next

5s. Calculate the acceleration of the bicycle in both the cases.​

Answer 1

Step-by-step explanation:

in first case

u=0m/s

v=6m/s

t=30sec

a=v-u/t

a= 6-0/30

a= 6/30= 0.2m/s

in second case

u=0m/s

v=4m/s

a=v-u/t

a= 4-0/5

a=0.8m/s

Answer 2

$\huge\mathfrak\pink{Solution}$

★ In the first case :

Initial Velocity, u = 0

Final velocity, v = 6 m s¯¹

Time, t = 30s

We have

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ a = $\frac{v - u}{t}$

Substituting the given values of u, v & t in the above equation, we get

‎ ‎ ‎ ‎ ‎ ‎ a = $\frac{(6m s¯¹ - 0 m s¯¹)}{30s}$

‎ ‎ ‎ ‎ ‎ ‎$\tt{\implies}$ 0.2m s¯¹

★ In the second case :-

Initial velocity, u = 6m s¯¹ ;

Final velocity, v = 4m s¯¹ ;

Time, t = 5s.

Then a = $\frac{(4m s¯¹ - 6m s¯¹)}{5s}$

$\tt{\implies}$ $\large\displaystyle{\boxed{\sf{\displaystyle{- 0.4m s¯¹}}}}$

The acceleration of the bicycle in the first case is 0.2m s¯¹ and in the second case, it is - 0.4m s¯¹

$\huge\mathfrak\pink{hope \ it's \ helps \ you}$