Question

Starting from a stationary position, Rahul paddles his bicycle to attain a velocity of 6ms^-1 in 30s.Then he applies
brakes such that the velocity
of the bicycle comes down to4ms^-1 in the next 5s. Calculate the acceleration of the bicycle in both the cases.
[Ans. 2ms^-2,-0.4 ms^-2]

Answer 1

Explanation:

CASE I

Given,

Initial Velocity(u)=0m/s

Final Velocity(v)=6m/s

time(t)=30 secs

Acceleration=?

v=u +at

v=0+a(30)

6=0+a(30)

6-0=a(30)

6/30=a

a=1/5 m/s-2

a=0.2m/s-2

CASE II

Given,

Initial Velocity(u)=6m/s

Final Velocity(v)=4m/s

time(t)=5 secs

acceleration=?

v=u+at

4=6+a(5)

4-6=a(5)

-2/5=a

a=-0.4m/s-2

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Answer 2

Answer:

a = 6-0/30= 0.2m/s^2

a = 4- 6/5= -2/5= -0.4m/s^2