Question

Starting from a stationary position Rahul paddles his bicycle to attain a velocity of 6m/s in 30s. Then he applies brakes such that the velocity of the bicycle comes down to 4m/s in the next 5s. Calculate the acceleration of the bicycle in both the case s.

Answer 1

In first case:-
Initial velocity (u)= 0
Final velocity(v)= 6m/s
Time= 30 sec.
v-u
a = ------
t
6 - 0
= -------- =0.2m/s^2
30

In second case:-
Initial velocity (u) = 6m/s
Final velocity (v) = 4m/s
Time = 5 sec.
v-u 4 - 6
a = --------- = ------- = - 0.4m/s^2
t 5

Answer 2

Answer:

$\huge\bf\red{AnsWer:}$

In the first case :

• Initial velocity , u = 0
• Final velocity , v = 6m/s
• time , t = 30 s

Therefore , a = acceleration =

a = v-u/t

➡️ 6-0/30

➡️ 0.2ms²

In the second case :

• initial velocity ,u = 6m/s
• final velocity , v = 4m/s
• time,t = 5s

Therefore acceleration =

a = v-u/t

➡️ 4-6/5

➡️ -0.4ms²