Question

Starting from a stationary position rahul paddles his bicycle to attain a velocity of 6m/s in 30 seconds. then he applies brake such tgat the velocity of his bicycle comes down to 4m/s in the next 5 seconds. calculate acceleration of the bicycle in both the cases.

Answer 1

Answer:IN FIRST CASE a= 1/5 m/s^2 or 0.2 m/s^2

              in second case a= -2/5 m/s^2 or -0.4 m/s^4

Explanation:

IN FIRST CASE

u= 0m/s (as the body starts from rest)

v=6m/s

a=v-u/t

v-u=6-0=6m/s

t=30s

....a= 6/30=1/5 m/s^2

IN SECOND CASE

u= 6m/s(as the body is slowing down from the final velocity of previous case)

v=4m/s

a=v-u/t

v-u=4-6= -2m/s

t= 5s

a= -2/5 m/s^2

HERE U GO!!