Starting from a stationary position, Usha paddles her bicycle to attain a velocity of 20ms-1 in 10seconds. Then she applies brakes in such that the velocity of the bicycle comes down to 5 ms-1 in next 5seconds. Calculate the acceleration of the bicycle in both the cases
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Answer:
Acceleration In first case = 2m/s
Acceleration in second case is = -4m/s ( Negative Acceleration)
Explanation:
first case
Initial velocity(u) is 0.
Final velocity is (v) is 20.
Time (t) is 10 seconds.
TO FIND ACCELERATION USE A = V-U÷T
SO , ACCELERATION IS 20-0 ÷ 10
A = 2m/s.
Acceleration In Second case
Initial velocity(u) is 20
Final velocity is (v) is 5
Time (t) is 5 seconds.
APPLYING THE SAME FORMULA A = V-U÷T
5-20 ÷ 5
ACCELERATION IS -4m/s.
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