Starting from rest a car moves on plane. The coeffi-
cient of friction (u) between the tyres and the plane
increases linearly with the distance (x). Kinetic energy
(K) of the car depends on x as
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Answer:
Support car moves a distance dx at a distance x.
μ=kx
f
r
=kx(mg)
Work done by friction =K.E(E)
E=f
r
dx=mgkxdx
E∝x
2
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