Starting from rest and moving with a constant acceleration,a body cover certain distance in time t. It covers the second half of the distance in a time
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Let the time taken to cover the first half portion of the journey be t1t1 and for the second half portion be t2t2 . Then
t=t1+t2t=t1+t2
For the first half-journey, putting
S=L/2,u=0S=L/2,u=0 etc. in S=ut+12S=ut+12at2at2, we get L2L2=0+12=0+12at21at12
L2L2=0+12=0+12at21at12
As the time to complete the whole journey is t, therefore ,
L=0+12L=0+12at2at2
Dividing both equations :
L=0+12L=0+12=>t1=t2–√=>t1=t2
t2=(t−t1)=t−t2√=t[2–√−12–√]
t=t1+t2t=t1+t2
For the first half-journey, putting
S=L/2,u=0S=L/2,u=0 etc. in S=ut+12S=ut+12at2at2, we get L2L2=0+12=0+12at21at12
L2L2=0+12=0+12at21at12
As the time to complete the whole journey is t, therefore ,
L=0+12L=0+12at2at2
Dividing both equations :
L=0+12L=0+12=>t1=t2–√=>t1=t2
t2=(t−t1)=t−t2√=t[2–√−12–√]
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