Starting from rest Deepak paddles his bicycle to attain a velocity of 6 m/s in 30 sec then he applies brakes so that the velocity of the bicycle comes down to 4 m/s in the next 5 sec . Calculate the acceleration of the bicycle in both the cases.
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Answer:
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Explanation:
CASE I
Given,
Initial Velocity(u)=0m/s
Final Velocity(v)=6m/s
time(t)=30 secs
Acceleration=?
v=u +at
v=0+a(30)
6=0+a(30)
6-0=a(30)
6/30=a
a=1/5 m/s-2
a=0.2m/s-2
CASE II
Given,
Initial Velocity(u)=6m/s
Final Velocity(v)=4m/s
time(t)=5 secs
acceleration=?
v=u+at
4=6+a(5)
4-6=a(5)
-2/5=a
a=-0.4m/s-2
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