Physics, asked by rituc6212, 4 hours ago

starting from stationary position, rahul paddles his bicycle to attain a velocity of 8 m/s in 32 sec. then he applied brakes such that the velocity of the bicycle comes down to 4 m/s in the next 5 sec. calculate the acceleration of the bicycle in both cases.​

Answers

Answered by ashishsinghsoftage
1

Answer:

0.25 m/s2 , - 0.8 m/s2

Explanation:

in 1st case

u = 0

v = 8 m/s

t = 32 s

a =( v-u) / t

a = (8 -0)/32

= 8/32

= 0.25 m/s2

In 2nd case

u = 8 m/s

v = 4 m/s

t = 5 s

a = (4-8)/5

a = - 4/5

= -0.8 m/s2

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