starting from stationary position, rahul paddles his bicycle to attain a velocity of 8 m/s in 32 sec. then he applied brakes such that the velocity of the bicycle comes down to 4 m/s in the next 5 sec. calculate the acceleration of the bicycle in both cases.
Answers
Answered by
1
Answer:
0.25 m/s2 , - 0.8 m/s2
Explanation:
in 1st case
u = 0
v = 8 m/s
t = 32 s
a =( v-u) / t
a = (8 -0)/32
= 8/32
= 0.25 m/s2
In 2nd case
u = 8 m/s
v = 4 m/s
t = 5 s
a = (4-8)/5
a = - 4/5
= -0.8 m/s2
Similar questions