Starting substance for the preparation of CH3Cl is
(a) CH3OH
(b) C2H5OH
(c) CH3CHO
(d) (CH3)2CO
Answers
Answered by
0
Heya,
The answer is (a).
CH3OH can be used for the preparation of CH3Cl by SN2 reaction using the reagent PCl3 or PCl5
Answered by
0
Answer:
option A is correct answer
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