Question

state and explain Ampere's circuital law​

Answer 1

State:

Ampere's Circuital Law states the relationship between the current and the magnetic field created by it.

Explanation:

This law states that the integral of magnetic field density (B) along an imaginary closed path is equal to the product of current enclosed by the path and permeability of the medium.

Answer 2

Ampere's circuital law states that if $\sf{\vec{B}}$ around any closed circuit is equal to $\sf{\mu_0}$ (permeability constant) times the total current I passing through this closed circuit.

$\succ$ Just as Gauss's law is an alternative form of Coulomb's law in electrostatics, similarly we have Ampere's circuital law as an alternative form of Biot-Savart law in magnetostatics.

$\succ$ Mathematically,

$\sf{\oint {\vec{B}} . {\vec{dl}} = {\mu_0} I}$