state and explain Gauss law of electrolysis and use it find the electric field intensity due to a hollow charged spherical conductor of the sphere
Answers
Answer:
Answer
Gauss Law:
Gauss law states that electric flux through any closed surface is equal to the net charge enclosed inside the surface divided by the permittivity of vacuum.
Electric field due to a uniformly charged thin shell:
In the diagram, O is the centre of the spherical shell of radius R, and charge enclosed by the spherical shell is q.
Let a point A is outside the spherical shell, where we have to calculate the electric field.The distance between the centre of spherical shell and the point A.
ϕ=E.Scosθ
So, ϕ=E.4πr
2
−−−−−−−−−−−−−−(1)
As per gauss law,
ϕ=
ϵ
o
q
−−−−−−−−−(2)
From equation (1) and (2)
E.4πr
2
=
ϵ
o
q
Now,
E=
4πϵ
o
r
2
q
This is the electric field at the distance r, outside from the shell.
Answer:
According to Gauss’s theorem the net-outward normal electric flux through any closed surface of any shape is equivalent to 1/ε0 times the total amount of charge contained within that surface.