state and prove basic proportionality theorem
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AD/BD =AE/CE
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AD/BD =AE/CE
This is the answer
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vishumadhup0703:
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Basic Proportionality Theorem (Thales theorem): If a line is drawn parallel to one side of a triangle intersecting other two sides, then it divides the two sides in the same ratio.
In ∆ABC , if DE || BC and intersects AB in D and AC in E then
AD AE
---- = ------
DB EC
Proof on Thales theorem :
If a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
Given : In ∆ABC , DE || BC and intersects AB in D and AC in E.
Prove that : AD / DB = AE / EC
Construction : Join BC,CD and draw EF ┴ BA and DG ┴ CA.
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