state and prove law of conservation of energy in case of a freely falling body
Answers
Law of conservation of energy states that the energy will neither be created nor destroyed however is reworked from one type to a different.
Let us currently prove that the on top oflaw holds smart within the case of a freely falling body.
Let a body of mass 'm' placed at a height 'h' on top of the bottom, start falling down from rest.
In this case we've got to indicate that the overall energy (potential energy + kinetic energy) of the body at A, B and C remains constant i.e, potential energy is
completely transformed into kinetic energy.
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At A, Potential energy = mgh
Kinetic energy mechanical energy = zero[the speed is zero because the object is ab initio at rest]
\ Total energy at A = mechanical energy + mechanical energy
Total energy at A = mgh …(1)
At B, Potential energy = mgh
= mg(h - x) [Height from the bottom is (h - x)] mechanical energy = mgh - mgx
Kinetic energy The body covers the space x with a speed v.
We create use of the third equation of motion to get speed of the body.
v2 - u2 = 2aS
Kinetic energy = mgx
Total energy at B = mechanical energy + mechanical energy
Total energy at B = mgh …(2)
At C, mechanical energy = m x g x zero (h = 0)
Potential energy = 0 Kinetic energy
The distance coated by the body is h v2 - u2 = 2aS
Kinetic energy
Kinetic energy = mgh
Total energy at C = mechanical energy + mechanical energy = zero + mgh
Total energy at C = mgh …(3) it's clear from equations one, two and three that the overall energy of the body remains constant at each purpose.
Thus, we have a tendency to conclude that law of conservation of energy holds smartwithin the case of a freely falling body.
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