State and prove Pythagoras theorem. Using this theorem, find the altitude of
an equilateral triangle ABC whose side is 2a.
Answers
Pythagoras theorem statement:-
“In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“
Proof:-
Let, ABC is a right angled triangle,right-angled at B
Therefore,
- AC = hypotenuse
- AB = adjacent side
- BC = perpendicular
To Prove :
- AC²= AB² + BC²
Construction: Draw a perpendicular BD meeting AC at D
From the diagram,
→ΔADB ~ ΔABC
As the corresponding sides of similar triangles are proportional,
⇒AD/AB = AB/AC
⇒AB²= AD × AC -------(1)
Also,
→ΔBDC ~ΔABC
As the corresponding sides of similar triangles are proportional,
⇒CD/BC = BC/AC
⇒ BC²= CD × AC -------(2)
Adding the equations (1) and (2),
⇒AB² + BC²= AD × AC+ CD × AC
⇒AB²+ BC² = AC (AD + CD)
We know,
- AD + CD = AC
Therefore,
Hence proved !
---------------------------
Altitude of an equilateral triangle whose side is 2a:-
Given:
- ABC is an equilateral triangle
- Side = 2a
To find:
- Altitude
Solution:
Let ABC be a equilateral triangle .
Therefore,AB=BC=AC=2a
AD is perpendicular on BC.
We know,
- Altitude of an equilateral triangle bisects opposite side
Hence,
→BD=CD=a
In ΔADB,
We have:
- AB = hypotenuse
- AD = perpendicular
- BC = base
By Pythagoras theorem,
Hence,
Length of altitude is √3a.
______________
Step-by-step explanation:
it is ok for you if yes please give thanks