State and prove the law of conservation of momentum.
( clearly state the meaning of each term stated by you and draw
appropriate diagram )
Answers
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11th
Physics
Laws of Motion
Newton's Second Law of Motion
State and prove the law of ...
PHYSICS
State and prove the law of conservation of momentum.
MEDIUM
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ANSWER
Law of conservation of momentum states that total momentum of system remains conserved in the absence of external force.
Proof:
Consider a body of mass m1 moving with velocity U1, striking against another body of mass m2 moving with velocity U2.
Let the two bodies remain in contact with each other for a small interval "delta t".
Let F12 be the average force exerted by mass m1 on m2, and let F21 be the force on m2 due to m1.
Let v1 and v2 be the velcoities of two bodies after collision.
Momentum of mass m1 before collision=m1u1
Momentum of mass m2 after collision=m2u2
Momentum of mass m1 after collision=m1v1
By using the definition of impulse, change in momentum of mass m1 is,
What would you like to ask?
11th
Physics
Laws of Motion
Newton's Second Law of Motion
State and prove the law of ...
PHYSICS
State and prove the law of conservation of momentum.
MEDIUM
Help best friend
Study later
ANSWER
What would you like to ask?
11th
Physics
Laws of Motion
Newton's Second Law of Motion
State and prove the law of ...
PHYSICS
State and prove the law of conservation of momentum.
MEDIUM
Help best friend
Study later
ANSWER
Law of conservation of momentum states that total momentum of system remains conserved in the absence of external force.
Proof:
Consider a body of mass m1 moving with velocity U1, striking against another body of mass m2 moving with velocity U2.
Let the two bodies remain in contact with each other for a small interval "delta t".
Let F12 be the average force exerted by mass m1 on m2, and let F21 be the force on m2 due to m1.
Let v1 and v2 be the velcoities of two bodies after collision.
Momentum of mass m1 before collision=m1u1
Momentum of mass m2 after collision=m2u2
Momentum of mass m1 after collision=m1v1
Answer:
m1 u1 + m2 u2 = m1 v1 + m2 v2
Step-by-step explanation:
pbc=pac
m1 u1 + m1 u2 = m1 v1 + m2 v2
dervation of truck :
a1 = (v1 - u1) / t
f1 =m1*a1
f1 = m1 * ( v1 -u1 )/t
derivation of car :
f2 = v2-u2 /t
= m2 * (v2-u2/t)
from 3rd law of motion : we know that to every there is an equal and opposite reaction
f1 =-f2
m1 * (v1 -u1)/t = -m2 ( v2 - u2)/ t
now time (t) can be cancelled from both the sides.
m1v1 -m1u1 = -m2v2 + m2u2
m1v1+m2v2= m1u1 + m2u2
m1u1 +m2u2 = m1v1+m2v2
a= acceleration
t= time
v= final velocity
u= intial velocity
m= mass
f = force