State and prove the Pythagoras theorem. Answers it fast please
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in a right angle triangle (hypotenuse)^2=(base)^2+(perpendicular)^2
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Defiition of Pythagorean theorem. : a theorem in geometry: the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.
right triangle consists of two legs and a hypotenuse. The two legs meet at a 90° angle and the hypotenuse is the longest side of the right triangle and is the side opposite the right angle. The Pythagorean Theorem tells us that the relationship in every right triangle is: a2+b2=c2. Example.
Given: A right-angled triangle ABC.
To Prove- AC2 = AB2 + BC2
Pythagoras Theorem Proof
Proof: First, we have to drop a perpendicular BD onto the side AC
We know, △ADB ~ △ABC
Therefore, ADAB=ABAC (Condition for similarity)
Or, AB2 = AD × AC ……………………………..……..(1)
Also, △BDC ~△ABC
Therefore, CDBC=BCAC (Condition for similarity)
Or, BC2= CD × AC ……………………………………..(2)
Adding the equations (1) and (2) we get,
AB2 + BC2 = AD × AC + CD × AC
AB2 + BC2 = AC (AD + CD)
Since, AD + CD = AC
Therefore, AC2 = AB2 + BC2
Hence, the Pythagorean thoerem is proved.