Question

state at which point during an oscillation the oscillator has zero velocity but negative acceleration? ​

Answer 1

Answer:

At the top point while the object is in a state of potential that means the point where the object could reach the farthest

Answer 2

To find:

At which point during an oscillation the oscillator has zero velocity but negative acceleration?

Solution:

Lets assume that an object is undergoing oscillation through simple harmonic motion. Now, let the amplitude be A.

$x = A \sin( \omega t)$

Now, velocity and acceleration is written as:

$\implies \: v = \omega \sqrt{ {A}^{2} - {x}^{2} }$

$\implies \: a = - { \omega}^{2} x$

• So, when the displacement from mean position is zero (i.e. x = 0) , the velocity is max and acceleration is zero.

• Similarly, when displacement from mean position is maximum (x = A), the velocity is zero and acceleration will be maximum and negative (i.e. opposite direction to displacement).

Hope It Helps.