Physics, asked by marwatkhan558, 11 hours ago

State Gauss's Law. Derive an expression for electric
intensity at a point close to a thin, infinites sheet of
positive charge.

Answers

Answered by madanlalsharma793
1

Explanation:

Gauss Law for electrostatics states that the total electric flux passing through a closed surface equals the enclosed charge in the surface divided by the permittivity of the medium.

ϕ

=∮(E

⋅ dS )= εo Q enenclose

Consider an infinite plane sheet of positive charge with charge density σ as shown in the attached figure. Electric field lines will be directed orthogonal and away from the sheet of charge. Hence, a cylindrical closed surface with its base parallel to the sheet of paper as shown in the figure is a good choice of Gaussian surface.

For the curved surface electric field is orthogonal to the surface area vector. Hence, flux linked to curved surface is zero.

Answered by Anonymous
2

Answer:

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