Question

state gausslaw and derive an expression for electric intensity due to uniformly charged spherical conductor by usi gausslaw
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Answer 1

Answer:

According to Gauss’s law, the total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The total electric flux through a closed surface is zero if no charge is enclosed by the surface.

Gauss’s law is true for any closed surface, no matter what its shape or size.

Let, R be the radius of the shell and Q be the charge uniformly distributed on the surface.  

i) For a point outside the shell :

By Gauss's law E.4πr²=q/ε0

here r be the distance from centre of shell (r>R) and charge enclosed by surface :Q  eq=Q

E out =E=Q/4πε0r²