state law of conservationof momentum and derive the same.
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✴️ LAW OF CONSERVATION OF MOMENTUM ✴️
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✔️law of conservation of momentum states that the sum of momentum of two objects before collision is equal to the sum of momentum after collision provided when there is no external unbalanced force acting on them.
✔️ momentum of object A before collision = m1u1
momentum of object B before collision = m2u2
total momentum of object A and B before collision = m1u1+m2u2
momentum of object A after collision = m1v1
momentum of object B after collision = m2v2
total momentum of object A and B after collision = m1v1+m2v2
FAB = m1v1 - m1u1 / t .................(i)
FBA = m2v2 - m2u2 / t ............(ii)
now, according to third law of motion
FAB = – FBA
=> m1v1 - m1u1 / t = – (m2v2 - m2u2 / t)
=> m1v1 - m1u1 = –m2v2 + m2u2
=> m1v1 + m2v2 = m1u1 + m2u2
=> m1u1 + m2u2 = m1v1 + m2v2
i.e. total Momentum before collision = total Momentum after collision. (PROVED)
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●▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬●
hope it will help you ✌️✌️
==================================
✴️ LAW OF CONSERVATION OF MOMENTUM ✴️
==================================
✔️law of conservation of momentum states that the sum of momentum of two objects before collision is equal to the sum of momentum after collision provided when there is no external unbalanced force acting on them.
✔️ momentum of object A before collision = m1u1
momentum of object B before collision = m2u2
total momentum of object A and B before collision = m1u1+m2u2
momentum of object A after collision = m1v1
momentum of object B after collision = m2v2
total momentum of object A and B after collision = m1v1+m2v2
FAB = m1v1 - m1u1 / t .................(i)
FBA = m2v2 - m2u2 / t ............(ii)
now, according to third law of motion
FAB = – FBA
=> m1v1 - m1u1 / t = – (m2v2 - m2u2 / t)
=> m1v1 - m1u1 = –m2v2 + m2u2
=> m1v1 + m2v2 = m1u1 + m2u2
=> m1u1 + m2u2 = m1v1 + m2v2
i.e. total Momentum before collision = total Momentum after collision. (PROVED)
=========
●▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬●
hope it will help you ✌️✌️
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