Question

State Newton's second law and give the relation between acceleration ,mass and force.

Answer 1

Newton's second law of motion

The second law of motion stated that "Acceleration of an object produced by net force is directly proportional to the magnitude of that net force and inversely proportional to the mass of the object if it is in the same direction of the net force".

The second law of motion is related to the behaviour of the objects to which there is Not balanced force. Writing this law in the form of equation, then it can be written as:

                          a = F / m

In simple terms, The same equation is written as:

                                F = m * a

"The most important thing to be remember in the 2nd equation of Motion is NET FORCE"

The direction of the Net force is in the same direction of acceleration. Hence, The direction of Acceleration and Net force is always same. So, if the net force is given or known, then indirectly we know about the acceleration also.

Problems based on Second Law of Motion:

• Net Force and Mass is given; we have to find acceleration.

Acceleration = Net force / Mass

• Mass and Acceleration is given; we have to find net force.

Net force = Mass * Acceleration

• Acceleration and Net force is given; we have to find Mass.

Mass = Force / Acceleration

Q. If the net force is 10 and mass 2 KG, find the acceleration ?

=> We know that,

Acceleration = Net force / Mass

Acceleration = 10 / 2

Acceleration = 5

Therefore, Acceleration is 5.

Problems based on Newton's second law are in this way.

Answer 2

Answer :

Newton's second law of motion states that the rate of momentum is directly proportional to the unbalanced Force applied on an object

Applied force ∝ Rate of change of linear momentum

$\sf \hookrightarrow \vec{F} = \frac{d \vec{p}}{d \vec{t}}\\ \\ \sf \hookrightarrow F= K \frac{d \vec{p}}{d \vec{t}} \\ \\\sf \hookrightarrow F = \frac{d(m \vec{v})}{dt} \: \: \: \{ \because k = 1 \} \\ \\\sf \hookrightarrow F = m \frac{d \vec{v}}{dt} \\ \\\sf \hookrightarrow F = m \vec{a} \: \: \: \{ \frac{ \: d \vec{v}}{dt} = \vec{ a \: }\}$

Therefore , the magnitude of force is F = ma

Where ,

F = force

m = mass

a = acceleration