Question

State second law of motion (NLM)

Answer 1

Answer:

✅Verified Answer✅

Seconds law.

We know momentum p=mv where m= mass and v=velocity,.

So rate of change of momentum Δp=mv−mu where v and u are the final and initial velocity.

So rate of change of momentum= M(V-U)/T

Also we know acceleration a= (v-u/t)

Again ForceF= Mass *Acceleration

F=M*A

Thus A can be written as Fα

Thus A can be written as Fα m(v−u)/T

F=kma where k= proportionality constant.

F=kma where k= proportionality constant.Hence from second law of motion we get force is the product of mass and acceleration.

F=kma where k= proportionality constant.Hence from second law of motion we get force is the product of mass and acceleration.F=ma..

Explanation:

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Answer 2

$\large\sf \bold{Newton's\: second \: law \: of \: motion }$

• "The rate of change of momentum is proportional to the applied force and the change of momentum occurs in the direction of force."

$\huge\sf{Momentum} \:$

Momentum is the product of mass and velocity of an object.

P = m v

{Momentum is a vector quantity.}

Suppose an object of mass 'm' has an initial velocity 'u'

When a force 'F' is applied in the direction of it's velocity for time 't', it's velocity becomes 'v'.

Initial momentum of object = mu

It's final momentum after time 't'= mv

Rate of change of momentum=

$\sf\frac{{change \: in \: momentum}} {time} \:$

Rate of change of momentum=

$\sf\frac{mv - mu}{t} = \frac{m(v - u)}{t} = ma \\ \\ </p><p></p><p> \sf( \frac{(v - u)}{t} = a)$

According to the second law of motion, the rate of change of momentum is proportional to the applied force.

$\sf{ma \: \: \alpha \: \: f \: }$

Therefore, F = k ma ( here, k = constant of Proportionality and it's value is 1.)

F = m.a

Remember that..

{If the same force is applied on different objects,the change of momentum is the same.}