Question

State the equations of motion of a free falling object from the equations of constant accelerated motion

Answer 1

Given State the equations of motion of a free falling object from the equations of constant accelerated motion

We know the general equation of motion is

       v = u + at

       s = ut + 1/2 at^2

      v^2 = u^2 + 2as

Now for a freely falling object we can replace acceleration a by g and distance s by h.

 So the equations can be written as

      v = u + gt

     h = ut + 1/2 gt^2

      v^2 = u^2 + 2gh

The initial velocity is zero when an object is dropped from a height.

The final velocity becomes zero when an object is thrown upwards.

The time taken is equal

The distance is directly proportional to the square of the time.