Question

✔️state the formula to find,
.csa, tsa and volume of frustum of a cone✔️​​

Answer 1

ANSWER

1)Cone

-It is a 3 - dimensional geometric figure that is sharp at one end and flat on another end.

-CSA (Curved Surface Area)

=> $\pi$ × r × l

Where,

r= Radius

l= slant height

-TSA (Total surface area)

=> $\pi$ × r × l + $\pi \times r^2$

=>$\pi$ × r [r+l]

-Volume

=>1/3 ×$\pi$×$\times r^2$×h.

2)Frustum of a cone

-CSA

=>$\pi$×l[R+r]

-TSA

=>$\pi$(r^2 + R^2)+$\pi$×l[R +r]

=>$\pi$[r^2 + R^2 + l{R +r}]

-Volume

=>$\dfrac{\pi\times h}{3}$[R^2 + r^2 +Rr]

-Slant height

=>l = $\sqrt{h^2 + (R-r)^2}$

Here =>

R=base radius

r= top Radius.

l=slant height

Answer 2

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$\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid }$

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$\Large\fbox{\color{purple}{QUESTION}}$

SURFACE AREA VOLUME FORMULAS

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$\Large\fbox{\color{purple}{ SOLUTION }}$

$\Large\mathcal\green{FRUSTUM}$

$\implies \: tsa = \pi \: l(r1 + r2) + \pi \: {r1}^{2} + \pi {r2}^{2}$

$\implies \: csa = \pi \: l(r1 + r2)$

$\implies volume = \frac{1}{3}\pi \: h( {r1}^{2} + r1.r2 + {r2}^{2} )$

$\implies slant \: hieght = \sqrt{h - ( {r1}^{2} + {r2}^{2}) }$

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