State the law of constant proportion.
A sample of ammonia contains 28 g nitrogen and 6 g hydrogen. Another sample contains 15 g hydrogen. Find the amount of nitrogen in the second sample.
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The amount of nitrogen in the second sample should be 70g.
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moles 1/2N2 in NH3=28/14=2mole
moles of 1/2H2 in NH3=6/3=2mole
therefore the second sample will also contain same mole ratio of both the atoms
mole ratio=2/2=1
moles of 1/2H2 in second sample=15/3=5mole
therefore mole of 1/2N2 in that sample=moles of H2 × mole ratio =5×1=5mole
mass of 1/2N2=14×5=70g
moles of 1/2H2 in NH3=6/3=2mole
therefore the second sample will also contain same mole ratio of both the atoms
mole ratio=2/2=1
moles of 1/2H2 in second sample=15/3=5mole
therefore mole of 1/2N2 in that sample=moles of H2 × mole ratio =5×1=5mole
mass of 1/2N2=14×5=70g
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