State the middle term of the following
Attachments:
Answers
Answered by
1
Answer:
10x^2-35x+30 =0
10x^2-15x-20x+30=0
5x(2x-3) -10(2x-3) =0
(5x-10) (2x-3) =0
5x-10=0, 2x-3=0
x=2, 3/2
Answered by
2
Answer:
10x^2-35x+30=0
=> 10x^2-20x-15x+30=0
=> 10x(x-2)-15(x-2)=0
=> (x -2) (10x-15)=0
Either x-2=0
x=0+2
=2
Or 10x-15=0
10x=0+15
x=15/10
=3/2
Similar questions