Question

state the netwon's second law of motion

Answer 1

Hey!!
Here is your answer..

$\bold{Newton's \: second \: law \: } \\ \bold{of motion}$

✓"The rate of change of momentum is proportional to the applied force and the change of momentum occurs in the direction of force."

$\bold{Momentum}$

Momentum is the product of mass and velocity of an object.
P = m v
{Momentum is a vector quantity.}

Suppose an object of mass 'm' has an initial velocity 'u'
When a force 'F' is applied in the direction of it's velocity for time 't', it's velocity becomes 'v'.

Initial momentum of object = mu

It's final momentum after time 't'= mv

Rate of change of momentum=
$\frac{{change \: in \: momentum}} {time}$

Rate of change of momentum=
$\frac{mv - mu}{t} = \frac{m(v - u)}{t} = ma$

$( \frac{(v - u)}{t} = a)$

According to the second law of motion, the rate of change of momentum is proportional to the applied force.

$ma \: \: \alpha \: \: f$

Therefore, F = k ma ( here, k = constant of Proportionality and it's value is 1.)

F = m.a

Remember that..
{If the same force is applied on different objects,the change of momentum is the same.}

Answer 2

Answer:-

The rate of change of linear momentum of a body is directly proportional to the external forces applied on the body, and this change take place in the direction of the force applied.

Suppose two bodies of different masses are initially a rest, and a fixed force is applied on them for a certain interval of time. To start with, the lighter body picks up a greater speed than the heavier body. However, at the end of the time interval, observations show that each body acquires the same linear momentum. It means that the same force applied for the same time cause the same change in momentum in bodies of different masses.

             The law implies that when a bigger force is applied on a body of given mass, its linear momentum changes faster and vice-versa. The momentum will change in the direction of the applied force.