Question

State the no. Of freedom possessed by a mono atomic molecule in space. Also give the expression for total energy possessed by it at a given temperature. Hence give the total energy of the atom at 300k.

Answer 1

Mono atomic gas atom : 

Degree of freedom = 3A - R 

3x1 -0 = 3 

as we know f = 3 

so total energy per molecule = 3/2 K(B) T 

K(x) = 1/2 K(B)T 

K(y) = 1/2 K(B)T

K(z) = 1/2 K(B)T

Given T = 300 K 

so Total energy = 3/2 K(B)T = 3/2 x 1.38 x 10⁻²³ x 300 

= 621 x 10⁻²³

= 6.21 x 10⁻²¹ joules