Question

state the relation between the refractive index and total internal reflection ?
class 10 th​

Answer 1

Answer:

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The relationship between critical angle and refractive index can be mathematically written as –

$SinC=\frac{1}{\mu _{b}^{a}}$

Where,

Where,C is the critical angle.

Where,C is the critical angle.μ is the refractive index of the medium.

Where,C is the critical angle.μ is the refractive index of the medium.a and b represent two medium in which light ray travels.

[ tex]{\blue {Critical \:angle\: and\: refractive\: index \:relation\: }}[/tex ]

[ tex]\blue{derivation}[/ tex]

[ tex]\huge\green{Applying\: Snells\: Law } [/tex ]

\frac{sin\;i}{sin\;r}=\frac{\mu _{a}}{\mu _{b}}

[ tex]\Rightarrow \mu _{b}sinC=\mu _{a}sin90^{0} [/tex]

[ tex]\Rightarrow \frac{\mu _{b}}{\mu _{a}}=\frac{1}{sinC} [/tex]

Explanation:

$\huge\mathcal{hope\:it\:helps\:you }$