Question

State the volume occupied by 40g of a hydrocarbon -CH4 at s.t.p if its vapour density is 8.

Answer 1

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Answer 2

The volume occupied by 40g of a hydrocarbon CH4 at s.t.p and vapor density 8 is 56 L.

Given:

Vapor density of hydrocarbon = 8

Mass of hydrocarbon = 40 g

To find:

Volume = ?

Formula to be used:

• Relative molecular mass = 2 × Vapor density

Calculation:

Relative molecular mass = 2 × Vapor density

Relative molecular mass = 2 × 8

Relative molecular mass = 16

∵ Volume of 16 g of $CH_4$ at STP = 22.4 L

Volume of 40 g of $CH_4$ at STP = X

On cross multiplication,

X × 16 = 40 × 22.4

X = $\frac{40\times22.4}{16}$

X = 11.2 × 5

X = 56.0

Conclusion:

The volume occupied by 40g of a hydrocarbon CH4 at s.t.p and vapor density 8 is calculated as 56 L.

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