Question

State True or False. Also write the reason foe your answer.

● An electron is released from rest at point A and moves towards point B. The potential at A is higher than potential at B.

● The positive terminal of a cell is connected to the end A, and the negative terminal is connected to the end B of a mettalic wire AB. Electrons flow in the wire in the direction B to A.

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Answer 1

1) Remember, W = Fd x d, where Fd A is the component of

E

yo Remember, W Fd x d, where Fd is the component of

the constant force along the direction of the motion.

Here, , so F = qE W qE y y qE y = ( f − o ) = Δ

- -

-

- -

B yf Electrostatic Potential

Energy (EPE)

2) Just like in a gravitational field, in an electric field, potential

energy (PE) can be converted into kinetic energy (KE):

Example: Let’s bring a small positive test charge from very far

away in toward a fixed, positive point charge:

As I push the charge in closer and closer, the repulsive force on it gets bigger and bigger

Answer 2

Answer :-

(1) False.

Explanation:- As Electron is released from point "A" which is at rest means Potential Difference is "Zero" at point A.

Hence, Potential Difference at "point A" can never be higher than Potential Difference at "Point B".

(2) True.

Explanation:- As we all know, Electrons are negatively charged particles and Negatively Charged particles always attracts towards Positively charged particles and repelled by Negatively charged particle.

So, when the current is passed through the Wire , they flow from Negative to Positive.