state universal law of gravitation what happens to the force if the distance between the object is decreased by 1by 6
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Universal law of gravitational is
F=Gm1*m2/(R^2)
m1 and m2 be mass of any Gtwo object
G is gravitational constant
And R is the distance of separation of m1 and m2
Let distance is decreased by 1/6
And new distance is d'=R/6
Apply gravitational law
F'=Gm1m2*36/R^2
F'=36F
New force is 36 times attractive than initial force of gravitational
Anonymous:
gravitational force is inversely proportional to the SQUARE the distance
Answered by
3
F = mM/r^2
then foece is inversaly prpotional to r^2
F ∝ 1/R^2
F/F' = 1/(1/6)^2
F/F' = 36/1
F = 36F'
then , new force is 36 times larger then old one
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