Question

State wheather 2x^2+5/2x-√3=0 is a quadratic equation or not ?
a. Yes
b. No ​

Answer 1

ɢɪᴠᴇɴ→

$2 {x}^{2} + \frac{5}{2x} - \sqrt{3} = 0$

ᴛᴏ ꜰɪɴᴅ→

Whether the given equation is a quadratic equation or not

ꜱᴏʟᴜᴛɪᴏɴ→

$→2 {x}^{2} + \frac{5}{2x} - \sqrt{3} = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ → \frac{2x(2 {x}^{2}) + 5 + 2x(- \sqrt{3})}{2x} = 0 \\ \\ →4 {x}^{3} + 5 - 2 \sqrt{3}x = 0 \times 2x \: \: \: \: \: \: \\ \\ →4 {x}^{3} - 2 \sqrt{3}x + 5= 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

→ No, it is not a quadratic equation as degree is not equal to 2. Degree of the equation is 3.

Answer 2

"

No

Step-by-step explanation:

.

Q.

2x² + 5/2x - √3 = 0 is a quadratic equation or not ?

.

Solution -

$\sf = > 2 {x}^{2} + \frac{5}{2x} - \sqrt{ 3} = 0 \\ \\ \sf = > 2x( {2x}^{2} + \frac{5}{2x} - \sqrt{3}) = 0 \\ \\ \sf= > 2x( {2x}^{2} ) + 2x( \frac{5}{2x} ) - 2x( \sqrt{3} ) = 0 \\ \\ \sf= > {4x}^{3} + 5 - 2 \sqrt{3} x = 0 \\ \\ \sf = > {4x}^{3} - 2 \sqrt{3} x + 5 = 0$

Here the highest power (degree) is 3, so it is not a quadratic equation, it's a cubic equation.

hope it helps.