state whether 7/80 will have a terminating or non terminating decimal expansion
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Hey mate!
Here is yr answer....
Terminating decimal :
~~~~~~~~~~~~~~~~~~
If the denomirator is in the form of 2^m × 5^n...then it is said to be a terminating decimal!
=> 7/80
= 7/2^4 × 5¹
by multiplying with 5³
= 7×5³/2^4×5¹×5³
= 7×125/2^4×5^4
= 875/(2×5)^4
= 875/10^4
= 875/10000
= 0.0875
Hope it helps...
#BB
= 7×
Here is yr answer....
Terminating decimal :
~~~~~~~~~~~~~~~~~~
If the denomirator is in the form of 2^m × 5^n...then it is said to be a terminating decimal!
=> 7/80
= 7/2^4 × 5¹
by multiplying with 5³
= 7×5³/2^4×5¹×5³
= 7×125/2^4×5^4
= 875/(2×5)^4
= 875/10^4
= 875/10000
= 0.0875
Hope it helps...
#BB
= 7×
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