Question

state whether the following
quadratic equations have two distinct
real roots justify your answer.
root 2X^2 - (3/root 2) + 1/root 2=0
10th math​

Answer 1

A quadratic equation, ax2 + bx + c = 0; a ≠ 0 will have two distinct real roots if its discriminant, D = b2 - 4ac > 0. Hence, the equation x2 –3x + 4 = 0 has no real roots. ... Hence, the equation 3x2 – 4x + 1 = 0 has two distinct real roots.

Answer 2

Answer:

= X1 = - ⁴√8/2 and X2 = ⁴√8/2 .

Que : 2x²-3/√2+1/√2 = 0

★ Solution :

Rationalise the denominator

= 2x²-3/√2+1/√2 = 0

= 2x²-3√2/√2+1/√2 = 0

= 2x²-3√2/2+√2/2 = 0

= 2x²- √2 = 0

= 2x² = √2

= x² = √2/2

= x = ± ⁴√8/2

= X1 = - ⁴√8/2 and X2 = ⁴√8/2 .