state which of the following are dimensionally current (i) Pressure= Energy per unit volume (ii) Pressure= Momentum x volume x time
Answers
Answered by
12
We know that [P] is ML^-1T^-2.
Now according to the question
[P] =[Energy] / [Volume]
ML-1T-2 =ML2T-2 / L3
= ML-1T-2
therefore it is dimensionally correct
Now second part
[P] = [Momentum] ×[Vol] ×[Time]
ML-1T-2 = MLT-1 × L3 × T
= ML4T0
we can observe and conclude that it is dimensionally incorrect.
Thus 1st one is correct.
Now according to the question
[P] =[Energy] / [Volume]
ML-1T-2 =ML2T-2 / L3
= ML-1T-2
therefore it is dimensionally correct
Now second part
[P] = [Momentum] ×[Vol] ×[Time]
ML-1T-2 = MLT-1 × L3 × T
= ML4T0
we can observe and conclude that it is dimensionally incorrect.
Thus 1st one is correct.
Urvashi09:
Hope this helps
Answered by
1
Answer:
1 at one is the correct answer
Explanation:
we know that [p] is ML^–2 T^–2
Now according to the Question
[P] =[ Energy ] / [ volume] .
ML^–1T^–2 = ML^2 T^–2 / L³.
= ML^–1T^–2 .
therefore it is dimensionally correct
[P] = [ Momentum] × [vol] ×[time] .
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