Question

Statement 1: A bullet of mass m gets embedded into a block and the system starts moving together, the collision is perfectly inelastic.
Statement 2: In perfectly inelastic collision, the bodies move together after the collision and momentum remains conserved.​

Answer 1

Explanation:

A particle of mass 'm' strikes a wedge of mass 'M' horizontally as shown in the figure.

STATEMENT-1 : If the collision is perfectly inelastic then, it can be concluded that the particle sticks to the wedge.

STATEMENT-2 : In perfectly inelastic collision velocity of both bodies is same along common normal just after the collision.

Answer 2

Answer:

both are correct

Explanation:

both statements are correct.

inelastic motion means velocity of seperation after collision should be zero.

so if bullet is embedded then they are not seperating so velocity of seperation is zero and it is inelastic motion

in all collisions momentum is conserved except there is an impulse since there is no impulse in statement 2 it is correct