Question

Statement-1 : KOH is more soluble in water than NaOH.
Statement-2 : NaOH is a stronger base than KOH. [2011]

Answer 1

Assertion is true but reason is false.

Explanation:

• We know both sodium and potassium are the alkali metals.

• Sodium has lower size, so has more compact lattice.

• Thus it has more lattice energy.

• Thus, the hydration enthalpy can more easily beat the lattice energy of potassium hydroxide than sodium hydroxide.

• So potassium hydroxide is more soluble than sodium hydroxide.

• Sodium, because of its lower size, has more polarising power.

• So its bond with hydroxide is more covalent in nature.

• Thus it cannot dissociate as easily as potassium hydroxide.

• So its less basic than potassium hydroxide.

For more information about hydration enthalpy,

https://brainly.in/question/7435670

Define hydration enthalpy - Brainly.in

https://brainly.in/question/7397031

relation between hydration enthalpy and electrode potential - Brainly ...

Answer 2

Statement-1 : KOH is more soluble in water than NaOH.

Statement-2 : NaOH is a stronger base than KOH.  

• KOH
• K - ionization is very low.
• K-O bond is more polar than N-O bond
• K-O bond breaks more easily and gives OH- ions.
• Therefore KOH is a stronger base than NaOH.
• The assertion "KOH is more soluble in water than NaOH" is correct, but,
• the reason "NaOH is a stronger base than KOH" is not correct.