Question

statement and reason​

Answer 1

Step-by-step explanation:

Given:-

MK = KO

∠MKJ = ∠OKJ (∵ JK is the bisector of ∠MKO)

To prove:-

∠M = ∠O

Proof:-

Considering ΔMKJ and ΔOJK

          MK = KO              (∵ Given)

         ∠MKJ = ∠OKJ    (∵ Given)

         JK = JK                 (∵ Common)

∴ ΔMKJ ≅ ΔOKJ, by SAS Congruency Rule.

∴ By CPCT, ∠M = ∠O