States newton's second law and derive an expression for force equals mass acceleration
Answers
Answered by
0
m(v-u)/t is the answer.
Answered by
1
Newton’s second law of motion states that: the net external force applied on an object is directly proportional to the rate of change of linear momentum of the object.
Let the external force be F, initial velocity be u ,final velocity be v, the time interval be t.
=> p1(initial momentum ) = mu
p2(final momentum )= mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s IInd law , F α Δp
=>F =k * (mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
=> F = ma
Hence proved
hope this will help u.. :-)
Let the external force be F, initial velocity be u ,final velocity be v, the time interval be t.
=> p1(initial momentum ) = mu
p2(final momentum )= mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s IInd law , F α Δp
=>F =k * (mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
=> F = ma
Hence proved
hope this will help u.. :-)
Similar questions