Physics, asked by Monikashaw9078, 1 year ago

States of “positronium” with chiral fermions?

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Answered by Anonymous
0
Hey mate ^_^

When I combine positron and electron to form positronium, or generically two spin 1/2 particles, I have four possible spin combinations that arrange into a singlet and a triplet state, which in turn are the trivial and standard representations of SO(3)....

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Answered by PrincessStargirl
2
That is, explicitly, AE/ma4 = -$, A, -3072, 95 -- 3i:2 and -& for the O-+('S,), l--(3S1), O++(3P0), l++(3P1) and l+-('P,) states respectively. Note that the annihilation terms in the 1-- state ofpositronium do not arise in the present case of two distinct fermion fields.

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