Question

Stationary waves of frequency 300 hz are formed in a medium in which the velocity of sound is 1200 m/s. The distance between a node and the neighbouring anti node is

Answer 1

Answer:

Frequency (f)= 300 Hz

Velocity of wave(v)= 1200m/s

Wavelength= d

$v \: = \: d \: \times \: f$

d=v/f

d=1200/300 m

d= 4 m

Distance between a node and neighbouring anti node= d/4= 4/4 m= 1 m

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