Physics, asked by amoghpatil407, 1 year ago

Stationary waves of frequency 300 Hz are formed in a medium in which the velocity of sound is 1200 m/s. Then the distance between a node and neighbouring antinode is​

Answers

Answered by rajeshsujal897
7

1200÷300=4

Hope it helps you

amoghpatil407: Thanks thats right ans.
Answered by tanks
4
distance between the node and neighbouring antinode =1200÷300
=4
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