Question

Statistics!

Find the mean and variance for first n natural numbers

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Answer 1

Answer:

mean = (n+1)/2

variance = (n²-1)/12

Step-by-step explanation:

Answer 2

Answer---> Mean= ( n + 1 ) / 2

Variance = ( n²- 1 ) / 12

To find ---> Mean and variance of first n natuaral number.

Solution--->

1) plzzz refer the attachment

2) We know that

a)1 + 2 +3 +.............+ n = n ( n + 1 ) / 2

b) 1² + 2² + 3² + .......+ n² = n ( n + 1 ) ( 2n + 1 ) / 6

c) Σ 1 = n

d) ( a - b )² = a² + b² - 2ab

Applying these formulee we get mean and variance of first n natural number