Question

Statue of Unity where is 48000 Newton and it exerts a pressure of 120 Pascal on the ground on which it stands find the area of its base​

Answer 1

$\large\red{\underline{\underline{\bf{\blue{Given}}}}}$

• Force (F) = 48000 Newton
• Pressure (P) = 120 Pascal

$\large\red{\underline{\underline{\bf{\blue{To \ Find}}}}}$

• Area (A) of its base

$\large\red{\underline{\underline{\bf{\blue{Solution}}}}}$

We know that,

➦ Force = Pressure × Area

➦ F = P × A

Put the above given values in, we get,

➭ 48000 = 120 × A

➭ A = 48000/120

➭ A = 400 m²

Hence,

• Area of Base (A) = 400 m²

Answer 2

$\Large{\underline{\underline{\tt{\purple{Given}}}}}$

• Force (F) = 48000N
• Pressure (P) = 120 P

$\Large{\underline{\underline{\tt{\purple{Find\:out}}}}}$

• Find the area of base

$\Large{\underline{\underline{\tt{\purple{Solution}}}}}$

As we know that

$\implies\sf P=\dfrac{F}{A} \\ \\ \\ \implies\sf 120=\dfrac{48000}{A} \\ \\ \\ \implies\sf 120A=48000 \\ \\ \\ \implies\sf A=\cancel\dfrac{48000}{120}=400m^2$

$\large{\underline{\boxed{\bf{\red{Area\:of\:statue=400m^2}}}}}$

$\Large{\underline{\underline{\tt{\purple{Extra\: Information}}}}}$

• Acceleration = v - u/t

• Force = mass × acceleration

• Speed = distance/time