Question

step by step answer please.​

Answer 1

Answer:

250*5 watts *28 days= 35 units in Feb month

and 4.5 WATS * 6*28= .756 unit

Explanation:

The exact answer depends on the question if it is a leap year.

kWh is exactly what it indicates, kilowatts multiplied by hours. The electric bulb uses 250 W = 0,25 kW times 5 hours = 1,25 kWh daily, the four 6 watt bulbs use 24 W together = 0,024 kW times 4,5 hours = 0,108 kWh daily. Total powerconsumtion for these 5 lights is 1,358 kWh daily.

In a 28 day february this is 38,024 kWh in total, in a 29 day february this is 39,382 kWh in total.

plz mark my answer has brainliest!!

Answer 2

Answer:

well na yen insta account delete panniten

Explanation:

a few days ago. so sorry and thanks